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A button cell used in watched funcations...

A button cell used in watched funcations as follwing
`Zn(s)+Ag_(2)O(s)+H_(2)O(l)hArr2Ag(s)+Zn^(2+)(aq.)+2OH^(-)(aq)`
If half cell potentials are
`Zn^(2+)(aq.)+2e^(-) rarr Zn(s), E^(@) = -0.76 V`
`Ag_(2)O(s)+H_(2)O(l)+2e^(-) rarr 2Ag(s)+2OH^(-)(aq.),, E^(@) = 0.34V`
The cell potential will be

A

1.10V

B

0.42V

C

0.84V

D

1.34V

Text Solution

Verified by Experts

The correct Answer is:
A

(a) Anode is always the site of oxidation thus, anode half - cell is
`Zn^(2+)(aq)+2e^(-) to Zn(s)," " E^(@)=-0.76 V`
Cathode half-cell is
`Ag_(2)O(s)+H_(2)O(l)+2e^(-) to 2Ag(s)+2OH^(-)(aq), E^(@)=0.34 V`
`E_(cell)^(@)=E_("cathode")^(@)-E_("anode")^(@)`
`=0.34-(-0.76)=+1.10V`
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A button cell used in watches functions as following Zn(s) + Ag _2 O(s) + H_2 O(l) 2 A g(s) + Zn^(2+) (aq) = 2 OH^- (aq) If half cell potentials are Zn^(2+) (aq) +2e^- rarr Zn (s) , E^@ =- 0. 76 V Af_2 O(s) +H_2 O (l) +2e^- rarr 2Ag(s) + 2OH^- (aq) , E^@ =0. 34 V . The cell potential will be .

In the button cells widely used in watches and other devices the following reaction takes place: Zn(s) + Ag_(2)O(s) + H_(2)O (l) to Zn^(2+) (aq) + 2Ag(s) + 2OH^(-)(aq) Determine DeltaG^(@) and E^(@) for the reaction Zn(s) to Zn^(2+) + 2e^(-) , E^(@) = 0.76 V Ag_(2)O + H_(2)O + 2e^(-) to 2Ag + 2OH^(-) E^(@) = +0.34 V

Consider Delta G^(@) for the following cell reaction : Zn (s) + Ag_(2)O(s)+H_(2)O(l) hArr Zn^(2+)(aq)+2Ag(s)+2OH^(-)(aq) E_(Ag^(+)//Ag)^(@) = +0.80 and E_(Zn^(2+)//Zn)^(@) = - 0.76 V

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