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Calculate the equilibrium constant of th...

Calculate the equilibrium constant of the reaction `:`
`Cu(s)+2Ag(aq) hArrCu^(2+)(aq) +2Ag(s)`
`E^(c-)._(cell)=0.46V`

A

`2.0xx10^(10)`

B

`4.0xx10^(10)`

C

`4.0xx10^(15)`

D

`2.4xx10^(10)`

Text Solution

Verified by Experts

The correct Answer is:
C
( c) `Cu(s)+2Ag^(2+)(aq) to Cu^(2+) (aq)+2Ag(s)`
`E^(@)=0.46 V " at " 298 K`
`RT ln K= nFE^(@)`
`IN K=(nFE^(@))/(RT)`
`ln K=(2xx0.46)/(0.0591)`
`K=3.68xx10^(15)~~4xx10^(15)`
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