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Reduction potential for the following h ...

Reduction potential for the following h alf-cell reaction are
`Zn rarr Zn rarr Zn^(2+)+2e^(-),E_(Zn^(2+)//Zn)^(@) = -0.76V`
`Fe rarr Fe^(2+)+2e^(-),E_(Fe^(2+)//Fe)^(@) = -0.44V`
The emf for the cell reaction
`Fe^(2+)Zn rarr Zn^(2+)+Fe`
will be

A

`+0.32V`

B

`-0.32V`

C

`+1.20V`

D

`-1.20V`

Text Solution

Verified by Experts

The correct Answer is:
A
(a) `E_(Zn^(2+)//Zn)^(@)=-0.76V`
`E_(Fe^(2+)//Fe)^(@)=-0.44V`
Cell reaction,
`Fe^(2+)+Zn to Zn^(2+) +Fe`
`E_(cell)^(@)=E_("(cathode)")^(@)-E_("(anode)")^(@)`
`=-0.44 -(-0.76)`
`=+0.32V`
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