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A 5A current in passed through a solutio...

A `5A` current in passed through a solution of zinc sulphate for `40 min`. These amount of zinc deposited at the cathode is

A

40.65 g

B

0.4065g

C

4.065g

D

65.04 g

Text Solution

Verified by Experts

The correct Answer is:
C
(c ) Current, I=5A
time t=40 min `=40xx60=2400 s`
Amount of electricity passed
Q=It
`Q=5xx2400`
`Q=12000 C`
`Zn^(2+) +2e^(-) to Zn `
`n=2e^(-)`
From Faraday first law
W=Zit
Z=equivalent mass [65.39=mass of zinc ]
`=("Mass")/(e^(-)xxF)`
`=(65.39)/(2xx96500)g` of zinc
therefore, 12000 C charge will deposite
`=(65.39xx12000)/(2xx96500)=4.065g` of zinc.
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