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Number of neutrons i8n a parent nucleus ...

Number of neutrons i8n a parent nucleus `X`, which gives `""_(7)^(14)N` after two sucessive `beta-` emission would be:

A

9

B

6

C

7

D

8

Text Solution

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The correct Answer is:
A

After emitting a `beta`particle atomic number is increased by one unit and atomic weight has no change .So the atomic number of parent nucleus
`5^(x^(14))overset(-beta)rarr_(6)Y^(14)overset(-beta)rarr_(7)^(14)`
Number of neutrons =mass number -number of protons
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