U^(235) + n^(1)rarr fission product + ne...

`U^(235) + n^(1)rarr` fission product + neutron + 3.2`xx 10^(-11)j`. The energy released , when 1g of `u^(235)` finally undergoes fission , is

`12.75xx10^(8)kj`

`18.60xx10^(9)kj`

`8.21xx10^(7)kj`

`6.55xx10^(6)kj`

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The correct Answer is:

235 g of u-235 contains `6.023xx10^(23)` atoms
1g u-235=`(6.023xx10^(23))/(235)atoms`
`therefore` Energy relaeased =`(3.2xx10^(-11)xx6.023xx10^(23))/(235)j`
`=8.21xx10^(10)j`
`8.21xx10^(7) kj`

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