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The correct of decreasing second ionisat...

The correct of decreasing second ionisation enthalpy of `Ti(22),V(23),Cr(24)` and `Mn(25)` is

A

`Cr gt Mn gt V gt Ti`

B

`V gt Mn gt Cr gt Ti`

C

`Mn gt Cr gt Ti gt V`

D

`Ti gt V gt Cr gt Mn`

Text Solution

Verified by Experts

The correct Answer is:
A
The amount of energy required to remove an electron from unipositive ion 1s referred as second ionisation potential.
In Ti, V, Cr and M.n, generally second ionisation energy increases with increases in atomic number but second ionisation potential of Cr is greater than that of Mn due to the presence of exactly half-filled d-subshell in Cr.
Thus, the order of second in ionisation enthalpy is
`Cr gt Mn gt V gt Ti`.
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