In a set reaction propionic acid yielded a compound `D`
`CH_(3)CH_(2)COOH overset (SOCI_(2)) to B overset (NH_(3)) to C overset (KOH)underset (Br_(2)) to D`
The structure of `D` would be

Options

A. `CH_3CH_2CH_2NH_2`
B. `CH_3CH_2CONH_2`
C. `CH_3CH_2NHCH_3`
D. `CH_3CH_2NH_2`

Answer

D

Explanation

For the reaction
`underset(A)(CH_(3)CH_(2)COOH) overset(SOCl_(2))underset({:(-SO_(2)),(-HCl):})to underset(B)(CH_(3)CH_(2)COCl) overset(NH_(3))underset(-HCl)to underset(C)(CH_(3)CH_(2)CONH_(2)) overset(4KOH+Br_(2))underset({:(-2KBr","-K_(2)CO_(3)","),(-2H_(2)O):})tounderset("(Ethyl amine)")underset(D)(CH_(3)CH_(2)NH_(2))`
Hence, it is also called Hofmann bromamide degradation reaction.
Hence, compound 'D' is `CH_3-CH_2-NH_2`
Hofmann bromamide reaction degrade the one C in amine product from amide.