Home
Class 11
MATHS
The area bounded by the curves y=cosx an...

The area bounded by the curves `y=cosx` and `y=sinx` between the ordinates `x=0` and `x=(3pi)/2` is

Text Solution

Verified by Experts

Area bonded by `y= cosx`and `y=sinx` between 0 to `(3pi)/2`
we have to divide are in three parts by seeing graph of which function is greater
therefore A=A1+A2+A3,where `A1 = int_0^(pi/4) (cosx-sinx)dx`=`sqrt2 -1`
now `A2 = int_(pi/4)^(3pi/4) (sinx-cosx)dx=2sqrt2`
`A3=int_(3Pi/4)^(3Pi/2)(cosx-sinx)dx=sqrt2-1`
now combining all three `A = 4sqrt2-2`
Promotional Banner

Similar Questions

Explore conceptually related problems

The area bounded by the curves y=cos x and y=sin x between the ordinates x=0 and x=3/2pi is:

Find the area bounded by the curves y= cos x and y= sin x between the ordinates x=0 and x= (3pi)/(2)

The area bounded by the curves y=cos x and y=sin x between the ordinates x=0 and x=3/2pi is :

The area bounded by the curves y = cos x and y = sin x between the ordinates x = 0 and x = (3pi)/(2) , is

The area bounded by the curves y = cos x and y = sin x between the ordinates x = 0 and x = (3pi)/(2) , is

The area bounded by the curves y = cos x y = sin x between the ordinates x =0 and x=3/2 pi is

The area bounded by the curesy y=cosxandy=sinx between the ordinates and x=(3pi)/(2) is

The area of the figure bounded by the curves y=cosx and y=sinx and the coordinates x=0 and x= pi//4 is