A charge of `10^(-9) C` is placed on each o fthe `64` idential drops of radius `2 cm`. They are then combined to from a bigger drop. Find its potential

27 identical drops, each charged to potential 10 volts, combined to form a bigger drop. Find potential of this bigger drop ?

There are 27 drops of a conducting fluid. Each has a radius r and they are charged to a potential V_(0) . They are then combined to form a bigger drop. Find its potential.

There are 27 drops of a conducting fluid. Each has a radius r and they are charged to a potential V_(0) . They are then combined to form a bigger drop. Find its potential.

There are 27 drops of a conducting fluid. Each has a radius r and they are charged to a potential V_(0) . They are then combined to form a bigger drop. Find its potential.

Sixty four spherical drops each of radius 2 cm and carrying 5 C charge combine to form a bigger drop. Its capacity is.

Sixty four spherical drops each of radius 2 cm and carrying 5 C charge combine to form a bigger drop. Its capacity is.

There are 27 drops of a conducting fluid. Each drop has radius r , and each of them is charged to the same potential V_1 . They are then combined to from a bigger drop. The potential of the bigger drop is V_2 . Find the ratio V_2//V_1 . Ignore the change in density of the fluid on combining the drops.

There are 27 drops of a conducting fluid. Each drop has radius r , and each of them is charged to the same potential V_1 . They are then combined to from a bigger drop. The potential of the bigger drop is V_2 . Find the ratio V_2//V_1 . Ignore the change in density of the fluid on combining the drops.

27 spherical drops, each carrying a charge of 10^(-3)muC that are at potential of 1,000 volts are combined to form a bigger drop. What would be the potential of this bigger drop?

A spherical drop of water carries a charge of 10xx10^(-12) C and has a potential of 100 V at its surface. If eight such charged drops combine to form a single drop, what will be the potential at the surface of the new drop?