The function `f(x)=(4sin^2x−1)^n (x^2−x+1),n in N`, has a local minimum at `x=pi/6` . Then (a) n is any even number (b) n is an odd number (c) n is odd prime number (d) n is any natural number

If the function f(x)=(4sin ^2 x-1)^n(x^2-x+1)n in N has a local maximum at x= pi //6 then n

B= {x:x in N and x is an even prime number }

If composite function f_1(f_2(f_3((f_n(x))))n timesis an increasing function and if r of f_i ' s are decreasing function while rest are increasing, then the maximum value of r(n-r) is (n^2-1)/4 , when n is an even number (n^2)/4, when n is an odd number (n^2-1)/4, when n is an odd number (n^2)/4, when n is an even number

If n is an odd number greater than 1, then n(n^(2)-1) is

Let f(x)=(x^(2)-1)^(n+1)+(x^(2)+x+1) Then f(x) has local extremum at x=1, when n is (A)n=2(C)n=4(B)n=3(D)n=5

n(n^(2)-1), is divisible by 24 if n is an odd positive number.

If f(x)=root(n)(x^(m)),n in N, is an even function, then m is even integer (b) odd integer any integer (d)f(x)- even is not possible

Let f(x)=(sin 2n x)/(1+cos^(2)nx), n in N has (pi)/(6) as its fundamental period , then n=