How does hydrogen peroxide behave in the reaction with `KIO_(4)`

Explanation

In this reaction, oxidation state of I decreases from +7 to +5. Therefore, it is gets reduced. This means `H_(2)O_(2)` acts as an oxidising agent
`overset(+7)(KIO_(4))+H_(2)O_(2) to overset(+5)(KIO_(3))+H_(2)O+O_(2)`