What happens when
(i) n-butyl chloride is treated with alcoholic KOH,
(ii) bromobenzene is treated with Mg in the presence of dry ether,
(iii) chlorobenzene is subjected to hydrolysis,
(iv) ethyl chloride is treated with aqueous KOH,
(v) methyl bromide is treated with sodium in the presence of dry ether,
(vi) methyl chloride is treated with KCN?

Explanation

(i). But-1-ene is formed as the product as a result of dehydrohalogention.
`underset("n-butyl chloride")(CH_(3)-CH_(2)-CH_(2)-CH_(2)-Cl)+KOH(alc)tounderset("But-1-ene")(CH_(3)-CH_(2)-CH=CH_(2))+KCl+H_(2)O`
(ii).
(ii). Phenyl magnesium bromide (grignard reagent) is formed as a result of the reaction.
(iii). Chlorobenzene will not get hydrolysed on boiling with NaOH. No product will be formed. For details,
(iv). Ethyl alcohol is formed as the product.
`underset("Ethyl chloride")(CH_(3)-CH_(2)-)Cl+KOH(aq)tounderset("Ethyl alcohol")(CH_(3)-CH_(2)-OH)+KCl+H_(2)O`
(v). Ehtane is formed as a result of Wurtz reaction.
`underset("Methyl bromide")(CH_(3)-Br)+2Na+Br-CH_(3)overset("Dry ether")tounderset("Ethane")(CH_(3)-CH_(3))+2NaBr`
(vi). Methyl cyanide is formed
`underset("Methyl chloride")(CH_(3)-Cl)+KCNunderset(("ethanol"))overset(KCN)tounderset(("Methyl cyanide"))underset("Acetonitrile")(CH_(3)-C-=N+)KCl`