A solution of aqueous of KO hydrolysis `CH_(3)CHClCH_(2)CH_(3) and CH_(3)CH_(2)CH_(2)CH_(2)Cl`. Which one of these is more easily hydrolysed.?

Explanation

To determine which compound is more easily hydrolyzed in the presence of aqueous KOH, we need to analyze the structures of the two haloalkanes given:

1. **Compound 1**: CH₃CHClCH₂CH₃ (2-chlorobutane)
2. **Compound 2**: CH₃CH₂CH₂CH₂Cl (1-chlorobutane)

### Step 1: Identify the type of halide
- **Compound 1 (2-chlorobutane)**: The chlorine atom is attached to a carbon that is bonded to two other carbon atoms (alkyl groups). This makes it a **secondary halide**.
- **Compound 2 (1-chlorobutane)**: The chlorine atom is attached to a carbon that is bonded to only one other carbon atom (and two hydrogen atoms). This makes it a **primary halide**.
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