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The vibration of a string of length 60 c...

The vibration of a string of length `60 cm` is represented by the equation,
`y = 3 cos (pix//20) cos(72pit)` where `x` & `y` are in `cm` and `t` in sec.
(i) Write down the compoent waves whose superposition gives the above wave.
(ii) Where are the nodes and antinodes located along the string.
(iii) What is the velocity of the particle of the string at the position `x = 5 cm` & `t = 0.25` sec.

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Verified by Experts

The correct Answer is:
(i) `y_(1) = 1.5 cos {(pi//20)x - 72pit}`,
`y_(2) = 1.5 cos {(pi//20)x + 72 pit)`
(ii) `10, 30, 50 cm` and `0 , 20 , 40 , 60 cm`
(iii) `0`
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