A circular loop of rope of length L rotates with uniform angular velocity `omega` about an axis through its centre on a horizontal smooth platform. Velocity of pulse (with resppect to rope ) produce due to slight radiul displacement is given by `(omegaL)/(2pi)` , if the motion of the pulse and rotation of the loop, both are in same direction then the velocity of the pulse w.r.t. to ground will be:

Options

A. `omegaL`
B. `(omegaL)/(2pi)`
C. `(omegaL)/(pi)`
D. `(omegaL)//(4pi^(2))`

Answer

C