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A circular loop of rope of length L rota...

A circular loop of rope of length L rotates with uniform angular velocity `omega` about an axis through its centre on a horizontal smooth platform. Velocity of pulse (with resppect to rope ) produce due to slight radiul displacement is given by `(omegaL)/2(pi)` ,if both are in opposite direction. Then the velocity of the pulse w.r.t. to groun will be:

A

`omegaL`

B

`(omegaL)/(2pi)`

C

`(omegaL)/(pi)`

D

`0`

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The correct Answer is:
D
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