Home
Class 12
PHYSICS
Two particle, each having a mass m are p...

Two particle, each having a mass `m` are placed at a separation `d` in a uniform magnetic field `B` as shown in figure.They have opposite charges of equal magnitude `q`.At time `t=0`, the particles are projected towards each other, each with a speed `v`.
Suppose `v=2v_(m)` and they stick to each other after the collision.Describe the motion after the collision (neglect the magnetic, gravitational & electric forces between charges).

A

circular motion

B

parbolic motion

C

elliptical motion

D

straight line

Text Solution

Verified by Experts

The correct Answer is:
D

`d=2R_(m)`
`d=2(mV_(m))/(qB)`
`V_(m)=(qBd)/(2m)`
Promotional Banner

Topper's Solved these Questions

  • ELECTRODYNAMICS

    RESONANCE|Exercise Exercise-3 PART-1|20 Videos
  • ELECTRODYNAMICS

    RESONANCE|Exercise Exercise-3 PART-2|27 Videos
  • ELECTRODYNAMICS

    RESONANCE|Exercise Exercise-2 PART-3 COMPREHENSION-2|3 Videos
  • ELECTRO MAGNETIC WAVES

    RESONANCE|Exercise Exercise 3|27 Videos
  • ELECTROMAGNETIC INDUCTION

    RESONANCE|Exercise A.l.P|19 Videos

Similar Questions

Explore conceptually related problems

Two particle, each having a mass m are placed at a separation d in a uniform magnetic field B as shown in figure.They have opposite charges of equal magnitude q .At time t=0 , the particles are projected towards each other, each with a speed v . What would be the maximum separation between the particles if v=v_(m)/4 ?

Two particle, each having a mass m are placed at a separation d in a uniform magnetic field B as shown in figure.They have opposite charges of equal magnitude q .At time t=0 , the particles are projected towards each other, each with a speed v . What would be the minimum separation between the particles if v=v_(m)/4 ?

Two particle, each having a mass m are placed at a separation d in a uniform magnetic field B as shown in figure.They have opposite charges of equal magnitude q .At time t=0 , the particles are projected towards each other, each with a speed v . At what instant will a collision occur between the particles if v=2v_(m) ?

Two particle, each having a mass m are placed at a separation d in a uniform magnetic field B as shown in figure.They have opposite charges of equal magnitude q .At time t=0, the particles are projected towards each other, each with a speed v . Find the maximum value v_(m) of the projection speed so that the two particle do not collide.

Two objects each of mass 5 kg are moving in the same straight line but in the opposite direction towards each other with some speed of 3 m/s. They stick to each other after collision. What will be the velocity of the combined object after collision?

A charge particle q of mass is placed at a distance d from another charge particle -2q of mass 2 m in a uniform magnetic field B as shown if particle are projected towareds each other with equal speed v_(0) , so that the two particle touches each other without collision during its motion (Assume only force due to magnetic field acts on the particle)