A ring of mass `m` and radius `r` is rotated in uniform magnetic field `B` which is perpendicular to the plane of the loop with constant angular velocity `omega_(0)`.Find the net ampere force on the ring and the tension developed in the ring if there is a current `i` in the ring.Current and rotation both are clockwise.

Answer

`0,r/(2pi)(momega_(0)^(2)+2piiB)`

Explanation

Net ampere force acting on a closed loop in uniform magnetic field is zero.
`2Tsin("d" theta)/2=(dm.r.omega^(2))+r."d" delta.iB`
`T."d" delta=m/(2pir).rd theta.r.omega^(2)+r."d" delta i.B`
`T=r/(2pi)(momega_(1)^(2)+2pi i.B)`.
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