Calculate `pH` of `10^(-7)M of NaOH` solution at `25^(@)C` (take log0.618=0.21)`

Explanation

To calculate the pH of a \(10^{-7} M\) NaOH solution at \(25^\circ C\), we will follow these steps:

### Step 1: Understand the dissociation of NaOH
NaOH is a strong base and dissociates completely in water:
\[ \text{NaOH} \rightarrow \text{Na}^+ + \text{OH}^- \]
Thus, the concentration of \(\text{OH}^-\) ions from NaOH is \(10^{-7} M\).
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