Calculate `pH` of mixture of `(400mL,(1)/(200)M H_(2)SO_(4))+(400mL.(1)/(100)M HCl)+(200mL of water)`
Take `log2=0.3`

Explanation

To calculate the pH of the given mixture, we will follow these steps:

### Step 1: Calculate the number of moles of \( H_2SO_4 \)
We have \( 400 \, \text{mL} \) of \( \frac{1}{200} \, \text{M} \, H_2SO_4 \).

\[ \text{Moles of } H_2SO_4 = \text{Concentration} \times \text{Volume} = \frac{1}{200} \, \text{mol/L} \times 0.4 \, \text{L} = 0.002 \, \text{mol} \]
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