Calculate degree of hydrolysis `K_(h)` and `pH` of `1M` urea hydtochloride solution in water `K_(b)` (Urea) `=1.5xx10^(-14)` at` 25^(@)C`.Consider urea as a monoacidic base.Take `log0.55=-0.26`

Explanation

`NH_(2)CONH_(3)Cl`is a salt of `SA+WB`
`K_(h)=(K_(W))/(K_(b))=(10^(-14))/(1.5xx10^(-14))=6.667xx10^(-1)`
Now `h=sqrt((K_(h))/(C))=sqrt((10^(-14))/(1.5xx10^(-14)xx1))`
or `h=0.816(gt0.1)` so we use actual relation
`K_(h)=(Ch^(2))/(1-h)=(1)/(1.5)`
`1.5h^(2)+h-1=0 rArr h=0.55`
`[H^(+)]=ch=0.55M`
`:.pH=0.26`