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Equal volume of 0.2M NH(4)OH (or ammonia...

Equal volume of `0.2M NH_(4)OH` (or ammonia) are `0.1MH_(2)SO_(4)` are mixed.Calculated pH of final solution.Given :`K_(b)` of `NH_(3)=1.8xx10^(-5)` at `25^(@)C`.

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To solve the problem of calculating the pH of the final solution when equal volumes of 0.2 M NH₄OH (ammonia) and 0.1 M H₂SO₄ (sulfuric acid) are mixed, we can follow these steps: ### Step 1: Determine the initial moles of NH₄OH and H₂SO₄ Let’s assume we mix 1 L of each solution for simplicity. - Moles of NH₄OH = 0.2 M × 1 L = 0.2 moles - Moles of H₂SO₄ = 0.1 M × 1 L = 0.1 moles ...
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