Calculate `pH` and degree of hydrolysis fo `10^(-2)MNH_(4)CN` solution.
Given that `K_(a)` of `HCN=5xx10^(-10)` and `K_(b)` of (aq.`NH_(3))=2xx10^(-5)` at `25^(@)C`.

Explanation

To calculate the pH and degree of hydrolysis for a \(10^{-2} \, \text{M} \, \text{NH}_4\text{CN}\) solution, we will follow these steps:

### Step 1: Determine the \(K_a\) and \(K_b\)
Given:
- \(K_a\) of HCN = \(5 \times 10^{-10}\)
- \(K_b\) of NH\(_3\) = \(2 \times 10^{-5}\)

### Step 2: Calculate \(K_w\)
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