The `pH` of a blood stream is maintained by a proper balance of `H_(2)CO_(3)` and `NaHCO_(3)` .What volume of `5MNaHCO_(3)` solution should be mixed with `10ml` of a sample of solution which is `2.5M` in `H_(2)CO_(3)` in order to maintain a `pH=7.4`(Take `pK_(a_(1))` for `H_(2)CO_(3)=6.7,log2=0.3)`

Explanation

`pH=pK_(a_(1))+log""([HCO_(3)^(-)])/([H_(2)CO_(3)])`
`rArr 7.4=6.7+log""([HCO_(3)^(-)])/([H_(2)CO_(3)]) rArr ([HCO_(3)^(-)])/([H_(2)CO_(3)])=5`
`:.5xx"moles of" H2CO3`=Moles of `HCO_(3)^(-)` (since both are components of same solution,volume of solution would be same for both)
`rArr :.5xx2.5xx10xx10^(-3)=5-VrArr "required volume"=0.025L=25mL`