Calculate similtaneous solubility of silver thiocyanate and silver bromids in water .Given that `K_(sp)` of silver thiocyanate=`10^(-12)` and `K_(sp)` of silver bromids `=5xx10^(-13)` respcectively.

Explanation

Let the simultaneous solubility of `AgSCN` be `x` and that of `AgBr` is `y`.Then:
`AgSCNhArr underset(x+y)(Ag^(+))+underset(x)(SCN^(-))"",,,,,,,,,,,""AgBrhArr underset(x+y)(Ag^(+))+underset(y)(Br^(-))`
`10^(-12)=xx(x+y)`....(i)
`5xx10^(-13)=y(x+y)`....(ii)
on solving we get `x=2y`
so `y=4.08xx10^(-7)M` and `x=8.16xx10^(-7)M`