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The solubility of Pb(OH)(2) in water is ...

The solubility of `Pb(OH)_(2)` in water is `6.7xx10^(-6)`M. Calculate the solubility of `Pb(OH)_(2)` in a buffer solution of `pH=8`.

Text Solution

Verified by Experts

`K_(sp)` of `Pb(OH_(2))=4s^(2)=4xx(6.7xx10^(-6))=1.203xx10^(-15)`
Now left solubility of `Pb(OH)_(2)`be smol litre^(-1) in it.
Thus `[Pb^(2+)][OH^(-)]^(2)=K_(sp)`
`[Pb^(2+)][10^(-6)]^(2)=1.203xx10^(-13) ` [Buffer has `pH=8,pOH=6 and [OH^(-)]=10^(-6)]`
`:.[Pb^(2+)]=(1.203xx10^(-15))/(10^(-12))=1.203xx10^(-3)` mol `"litre"^(-1)`
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