A solution of `HCl` has a `HCl` has a `pH=5` if one mL of it is dilluted to `1` litre what will be `pH` of resulting solution.

Explanation

`[HCl]_(f)=10^(-5)M` since `pH=5`
since volume of original solution has been made `1000` times so concentrated of solution will decrease by `1000` times.
`[HCl]_(f)=10^(-8)M` so `H^(+)` form water should also be considered (as done in solved example-8)
then `pH` of resulting solution =`6.96`.