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Acetic acid gets 1.3% ionised in its dec...

Acetic acid gets `1.3%` ionised in its decimolar solution.What is be the ionisation constant of acetic acid?

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`K_(a)=(Calpha^(2))/(1-alpha)&alpha=(1.3)/(100)=0.013`
`C=0.1 M`
`alpha lt0.1"therefore"K_(a)=calpha^(2)`
`=0.1xx(0.013)^(2)=1.69xx10^(-5)`
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