What is `[HS^(-)] & [S^(2-)]` in solution of `0.01M HCl` and `0.1 M H_(2)S` ?(Given that for `H_(2)S,K_(a_(1))=10^(-7)and K_(a_(2))=10^(-14))`

Explanation

To find the concentrations of \([HS^-]\) and \([S^{2-}]\) in a solution of \(0.01M\) HCl and \(0.1M\) \(H_2S\), we can follow these steps:

### Step 1: Determine the concentration of \(H^+\) ions from HCl
Since HCl is a strong acid, it completely dissociates in solution. Therefore, the concentration of \(H^+\) ions from \(0.01M\) HCl is:
\[ [H^+] = 0.01 \, M \]

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