On adding `0.04g` solid `NaOH` to a `100mL,(M)/(200)Ba(OH)_(2)` solution, determine change in `pH`:

Options

A. `0`
B. `+0.3`
C. `-0.3`
D. `+0.7`

Explanation

To determine the change in pH when adding 0.04 g of solid NaOH to a 100 mL solution of Ba(OH)₂ with a concentration of 1 M, we will follow these steps:

### Step 1: Calculate the number of moles of Ba(OH)₂ in the solution
The concentration of Ba(OH)₂ is given as 1 M (1 mol/L), and the volume of the solution is 100 mL (0.1 L).

\[ \text{Number of moles of Ba(OH)}_2 = \text{Concentration} \times \text{Volume} = 1 \, \text{mol/L} \times 0.1 \, \text{L} = 0.1 \, \text{mol} \]
...