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pH of solution obtained by mixing equal ...

`pH` of solution obtained by mixing equal volumes of `0.1M` Triethyl amine `(K_(b)=6.4xx10^(-5))` & `(4)/(45)M NH_(4)OH (K_(b)=1.8xx10^(-5))` will be :

A

`11.3`

B

`10.3`

C

`12.3`

D

`11.45`

Text Solution

Verified by Experts

`[OH^(-)]=sqrt((0.1xx6.4+(4xx1.8)/(45))xx10^(-5))=0.002M :.pH=11.3`
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RESONANCE-IONIC EQUILIBRIUM-Part -II (only one option correct type)
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