In a solution containing `0.1M HCl & 0.1M H_(3)PO_(4)` (having dissociation constants `K_(a_(1)),K_(a_(2)),K_(a_(3)))` assuming `alphaltlt1` for `H_(3)PO_(4)`,

Options

A. `pH=1`
B. `alpha_(H_(3)PO_(4))=10K_(a_(1))`
C. `[HPO_(4)^(2-)]=10K_(a_(1))K_(a_(2))`
D. All of these

Explanation

`[H^(+)]=0.1M`& `pH=1`
`K_(a_(1))=(0.1[H_(2)PO_(4)^(-)])/(0.1)rArr [H_(2)PO_(4)^(-)]=K_(a_(1))rArrCalpha=K_(a_(1))rArr alpha=(K_(a_(1)))/(0.1)=10K_(a_(1))`
`K_(a_(2))=(0.1[HPO_(4)^(-)])/(K_(a_(1)))rArr[HPO_(4)^(-)]=K_(a_(1))xxK_(a_(2))xx10`