For a solution obtained by mixing equal volumes of `0.02M KOH` solution `&0.2MB` (weak diacidic base),` K_(b_(1))=10^(-7) & K_(b_(2))=10^(-14))` solution:

Options

A. `pH=12`
B. `[BH^(+)]=10^(-6)M`
C. `[BH_(2)^(2+)]=10^(-18)M`
D. All of these

Explanation

To solve the problem, we will follow these steps:

### Step 1: Calculate the concentration of OH⁻ ions after mixing
When we mix equal volumes of 0.02 M KOH and 0.2 M B, the concentrations will change due to dilution.

- The concentration of KOH before mixing is 0.02 M.
- After mixing equal volumes, the concentration of KOH becomes:
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