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10 mL of a strong acid solution of pH=2....

10 mL of a strong acid solution of `pH=2.000` are mixed with 990mL of another strong acid solution of `pH=4.000`. The pH of the resulting solution will be:

A

`3`

B

`3.3`

C

`3.7`

D

Molecular formula of both strogn acids should be known to answer above question.

Text Solution

Verified by Experts

`[H^(+)]` after mixing =`(10^(-2)xx10+10^(-4)xx990)/(1000)=(0.1+0.0990)/(1000)=(0.1990)/(1000)=1.99xx10^(-4)`
`pH=4-0.3=3.7`
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