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What concentration of OH^(-) ions will r...

What concentration of `OH^(-)` ions will reduce `NH_(4)^(+)` ion to `2xx10^(-5)M` in `0.4M` solution of `NH_(4)OH ? K(b)(NH_(4)OH)=1.8xx10^(-5)`

A

`0.36M`

B

`0.036M`

C

`2xx10^(-5)M`

D

None of these

Text Solution

Verified by Experts

`{:(,NH_(4)OHhArr,NH_(4)^(+),+,OH^(+)),(t=eq,0.4(1-alpha),2xx10^(-5),,),(,,(=0.4alpha),,):}`
So,`alpha=5xx10^(-5)(ltlt1):.0.4(1-alpha)~~0.4`
`K_(b)=(2xx10^(-5)xx[OH^(-)])/(0.4)=1.8xx10^(-5)rArr [OH^(-)]=0.36M`
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