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0y=e^({xy)|graph...

0y=e^({xy)|graph

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If y= e^(xy), then (dy)/(dx) =

The curve y-e^(xy)+x=0 has a vertical tangent at the point:

The curve y-e^(xy)+x=0 has a vertical tangent at the point

The curve y-e^(xy)+x=0 has a vertical tangent at the point :

The curve y-e^(xy)+x=0 has a vertical tangent at the point :

The curve y-e^(xy)+x=0 has a vertical tangent at the point :

The curve y-e^(xy)+x=0 has a vertical tangent at the point:

Draw the graph of y=e^(-x), when the graph of y=e^(x) is known.

Draw the graph of y=-e^(x) when the graph of y=e^(x) is known.