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The silicate anion in the mineral Kionit...

The silicate anion in the mineral Kionite is a chain of three `SiO_(4)` tetrahedra that share corners with adjacent tetrahedra. The mineral also contains `Ca^(2+)` ions, `Cu^(2+)` ions, and water molecules in a `1:1:1` ration.
(a) Give the formula and charge of the silicate anion.
(b) GIve the complete formula for the mineral.

Text Solution

Verified by Experts

(a)The silicate anion has three `SiO_(4)` tetrahedra that share corners with adjacent tetrahedra thus silicate is `Si_(3)O_(10)` , hence it can be represented as with charge as =`3xx4n+10xx(-2)=-8`
`[O-undersetunderset(O)(|)oversetoverset(O)(|)(Si)-O-undersetunderset(O)(|)oversetoverset(O)(|)(Si)-O-undersetunderset(O)(|)oversetoverset(O)(|)(Si)-O]^(8-)`
(b)`Ca^(2+),Cu^(2+)` and `H_(2)O` are in the ratio of `1:1:1` and to balance `(-8)` charge of silicate as ion, `(+8)` charge is required thus there are two units each of `Ca^(2+),Cu^(2+)` and `H_(2)O` thus, kinotie has formula `Ca_(2),Cu_(2),Si_(3),O_10).2H_(2)O`
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