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Three moles of B(2)H(6) are completely r...

Three moles of `B_(2)H_(6)` are completely reacted with methanol. The number of moles of boron containing product formed is.

Text Solution

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`B_(2)H_(6)+6CH_(3)OHto2B(OCH_(3))_(3)+6H_(2)`
For `3` moles of `B_(2)H_(6)` mole of `B` containing product formed =`6`
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