A compound of boron X reacts at `200^(@)C` temperature with `NH_(3)` to give another compound Y which is called as inorganic benzene. The compound Y is a colourless liquid and is highly light sensitive. Its melting point is `-57^(@)C`. The compound X with excess of `NH_(3)` and at a still higher temperature gives boron nitride `(BN)_(n)`. The compounds X and Y are respectively:

Options

A. `BH_(3)` and `B_(2)H_(6)`
B. `NaBH_(4)` and `C_(6)H_(6)`
C. `B_(2)H_(6)` and `B_(3)N_(3)H_(6)`
D. `B_(4)C_(3)` and `C_(6)H_(6)`

Answer

C

Explanation

The reactions involved are
`underset((X))(3B_(2)H_(6))+6NH_(3)to underset((Y))(2B_(3)N_(3)H_(6))+12H_(2) , B_(2)H_(6)+NH_(3)("excess")overset("at higher temperature")to(BN)_(n)+H_(2)`
`Y` is borazole which is isosteric with benzene.