Elements `A, B, C, D` and `E` have the following electronic configurations:
A: `1s^(2) 2s^(2) 2p^(1)` B: `1s^(2) 2s^(2) 2p^(6) 3s^(2) 3p^(1)`
C: `1s^(2) 2s^(2) 2p^(6) 3s^(2) 3p^(2)` D: `1s^(2) 2s^(2) 2p^(6) 3s^(2) 3p^(5)`
E: `1s^(2) 2s^(2) 2p^(6) 3s^(2) 3p^(6) 4s^(2)`
Which among these will belong to the same group in the periodic table?

Options

A. A & B
B. B & C
C. C & D
D. D & E

Answer

A

Explanation

Out of these, elements `A` and `B` will belong to the same group of the periodic table because they have same outer electronic configuration, `ns^(2) np^(1)`.