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Atomic radius of Li is 1.23 Å and ionic ...

Atomic radius of `Li is 1.23 Å` and ionic radius of `Li^(+)` is `0.76 Å`. Calculate the percentage of volume occupied by single valence electron in `Li`.

Text Solution

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Volume of `Li = (4)/(3) xx 3.14 xx (1.23)^(3) = 7.79 Å (-Li = 1s^(2) 2s^(1))`
Volume of `Li^(+) = (4)/(3) xx 3.14 xx (0.76)^(3) = 1.84 Å (Li^(+) = 1s^(2))`
`:.` Volume occupied by `2s` subsheel `= 7.79 - 1.84 = 5.95 Å`.
`%` volume occupied by single valence electron i.e., `2s` electron `= (5.95)/(7.79) xx 100 =76.4%`.
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