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Ionisation energy and electron affinity ...

Ionisation energy and electron affinity of fluorine are respectively `17.42` and `3.45 eV`. Calculate electronegativity of fluorine atom.

Text Solution

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The correct Answer is:
`chi_(P) = 3.726`
According to Mulliken's electronegativity `(chi_(M)) = ("Ionisation energy +Electron affinity")/(2)`
`= (17.42 +3.45)/(2) = 10.435`
Therefore, electronegativity on Pauling's scale `(chi_(P)) = (10.435)/(2.8) = 3.726`
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