Writen the atomic number of the element present in the fourth period and eighth group of the Modern periodic table.

Answer

To find the atomic number of the element present in the fourth period and eighth group of the Modern Periodic Table, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Fourth Period:**
The fourth period of the Modern Periodic Table includes elements with atomic numbers ranging from 19 to 36. This means the elements in this period are:
- Potassium (K, Z=19)
- Calcium (Ca, Z=20)
- Scandium (Sc, Z=21)
- Titanium (Ti, Z=22)
- Vanadium (V, Z=23)
- Chromium (Cr, Z=24)
- Manganese (Mn, Z=25)
- Iron (Fe, Z=26)
- Cobalt (Co, Z=27)
- Nickel (Ni, Z=28)
- Copper (Cu, Z=29)
- Zinc (Zn, Z=30)
- Gallium (Ga, Z=31)
- Germanium (Ge, Z=32)
- Arsenic (As, Z=33)
- Selenium (Se, Z=34)
- Bromine (Br, Z=35)
- Krypton (Kr, Z=36)

2. **Identify the Eighth Group:**
The eighth group in the Modern Periodic Table corresponds to the transition metals, specifically the group that includes Iron (Fe), Cobalt (Co), and Nickel (Ni). In the fourth period, the eighth group is represented by Iron (Fe), which has an atomic number of 26.

3. **Conclusion:**
Therefore, the atomic number of the element present in the fourth period and eighth group of the Modern Periodic Table is **26**.

### Final Answer:
The atomic number of the element present in the fourth period and eighth group is **26**.

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