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In the ionic compound KF, the K^(+) and ...

In the ionic compound `KF`, the `K^(+)` and `F^(-)` ions are found to have practically identical radii, about `1.34 Å` each. What can you predict about the relative atomic radii of `K & F`?

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The correct Answer is:
Atomic radius of `K` is larger than `F` because the size of cation is smaller than its parent atom while size of anion is bigger than its parent atom. Thus, atomic radii of `K` will be greater than 1.34 `Å` while atomic radii of `F` will be less than 1.34 `Å`.
Atomic radius of `K` is larger than `F` because the size of cation is smaller than its parent atom while size of anion is bigger than its parent atom. Thus, atomic radii of `K` will be greater than 1.34 `Å` while atomic radii of `F` will be less than 1.34 `Å`.
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