Atomic number of `Ag` is 4.7. in the same group, the atomic numbers of elements placed above and below `Ag` in Long form of periodic table will be:

Options

A. 26, 95
B. 39,79
C. 29,79
D. 39,65

Answer

C

Explanation

Silver belongs to `V^(th)` period. So the atomic number of element placed above and below will be `47 - 18 = 29` and `47 +32 = 79` respectively.