`{:(A^(-) (g) rarr A^(2+)(g),,DeltaH = 1100KJ//mol),(A(g)rarrA^(2+)(g),,DeltaH = 1200 KJ//mol):}`
Electron gain enthalpy of `A` is `P xx 10^(2) KJ//mol`. What is the value of `P`?

Answer

1

Explanation

`A(g) +e^(-) rarr A^(-)(g) DeltaH = + E.G.E ….(1)`
`A(g) rarr A^(2+) (g)+2e^(-) DeltaH = 1200 KJ//mol ……..(2)`
`A^(-)(g) rarr A^(2+)(g)+3e^(-) DeltaH = 1100 KJ//mol ……(3)`
`Eq.(3) = (2) - (1)`
`- E.G.E +1200 = 1100`
`-E.G.E =- 100 kJ//mol`
`P = 1`.