Statement-1 :Acidified K(2)Cr(2)O(7) sol...

Statement-1 :Acidified `K_(2)Cr_(2)O_(7)` solution becomes green when `SO_(2)` gas is passed through it.
Statement-2 :This is an redox reaction.

A

STATEMENT-1 is true, STATEMENT-2 is true and STATEMENT-2 is correct explanation for STATEMENT-1

B

STATEMENT-1 is true, STATEMENT-2 is true and STATEMENT-2 is not correct explanation for STATEMENT-2

C

STATEMENT-1 is true, STATEMENT-2 is false

D

STATEMENT-1 is false, STATEMENT-2 is true

Verified by Experts

The correct Answer is:

B

Similar Questions

Explore conceptually related problems

$ Acidified K_(2)Cr_(2)O_(7) is turned green when SO_(2) is passed thorugh it. ! In this reaction SO_(2) acts as a reducing agent.

SO_(2) reduces acidified K_(2)Cr_(2)O_(7) to

Acidified K_(2)Cr_(2)O_(7) solution turns green when Na_(2)SO_(3) is added to it. This is due to the formation of

Acidified K_(2)Cr_(2)O_(7) solution turns green when NasO_(3) is added to it. This is due to the formation of :

Acidified K_(2)Cr_(2)O_(7) , solution turns green when Na_(2)SO_(3) is added to it. Thus is due to the formation of

In the reaction with acidified K_(2)Cr_(2)O_(7) solution , SO_(2) acts as