Find the hybridization state of each carbon atoms in following compound?
`CH_(2)=C=CH-CH_(2)-C=C-CH_(2)-NH_(2)`

Answer

To determine the hybridization state of each carbon atom in the compound `CH2=C=CH-CH2-C=C-CH2-NH2`, we will analyze the bonding and geometry around each carbon atom step by step.

### Step 1: Identify the structure of the compound
The compound can be represented as follows:
```
H H H H H
| | | | |
H2C=C=C-CH2-C=C-CH2-NH2
```
This shows the arrangement of carbon and hydrogen atoms, along with the amino group (NH2).

### Step 2: Count the bonds for each carbon atom
1. **First Carbon (C1)**: `CH2` - This carbon is bonded to 2 hydrogens and 1 carbon (C2) through a double bond. Total bonds = 3 (2 sigma from H and 1 sigma from C2).
2. **Second Carbon (C2)**: `C` - This carbon is involved in a double bond with C1 and C3. Total bonds = 3 (1 sigma with C1 and 2 pi with C3).
3. **Third Carbon (C3)**: `C` - This carbon is involved in a double bond with C2 and a single bond with C4. Total bonds = 3 (1 sigma with C2 and 1 sigma with C4).
4. **Fourth Carbon (C4)**: `CH2` - This carbon is bonded to 2 hydrogens and 1 carbon (C3) through a single bond. Total bonds = 4 (2 sigma from H and 1 sigma from C3).
5. **Fifth Carbon (C5)**: `C` - This carbon is involved in a double bond with C4 and a single bond with C6. Total bonds = 3 (1 sigma with C4 and 2 pi with C6).
6. **Sixth Carbon (C6)**: `C` - This carbon is involved in a double bond with C5 and a single bond with C7. Total bonds = 3 (1 sigma with C5 and 2 pi with C7).
7. **Seventh Carbon (C7)**: `CH2` - This carbon is bonded to 2 hydrogens and 1 carbon (C6) through a single bond. Total bonds = 4 (2 sigma from H and 1 sigma from C6).

### Step 3: Determine the hybridization
- **C1**: 3 bonds → sp² hybridization
- **C2**: 3 bonds → sp hybridization
- **C3**: 3 bonds → sp² hybridization
- **C4**: 4 bonds → sp³ hybridization
- **C5**: 3 bonds → sp hybridization
- **C6**: 3 bonds → sp hybridization
- **C7**: 4 bonds → sp³ hybridization

### Summary of Hybridization States
- C1: sp²
- C2: sp
- C3: sp²
- C4: sp³
- C5: sp
- C6: sp
- C7: sp³