The general formula `C_(n)H_(2n)O_(2)` could be for open chain

Options

A. diketones
B. carboxylic acids
C. diots
D. dialdehydes.

Explanation

To determine which of the given compounds has the carboxylic functional group (COOH) and fits the general formula \( C_nH_{2n}O_2 \), we will analyze each compound step by step.

### Step 1: Identify the Compounds
The compounds given are:
1. Picric acid
2. Barbituric acid
3. Ascorbic acid
4. Aspirin

### Step 2: Draw the Structures
We will draw the structures of each compound to identify the presence of the carboxylic group (COOH).

1. **Picric Acid**:
- Structure: It is a phenolic compound with three nitro groups attached to the benzene ring.
- Carboxylic Group: **Absent**.

2. **Barbituric Acid**:
- Structure: It contains a pyrimidine ring with multiple carbonyl (C=O) groups and an amine group.
- Carboxylic Group: **Absent**.

3. **Ascorbic Acid**:
- Structure: It has multiple hydroxyl (OH) groups and a lactone structure, but does not contain a carboxylic acid group.
- Carboxylic Group: **Absent**.

4. **Aspirin**:
- Structure: It contains a carboxylic acid group (COOH) and an ester group.
- Carboxylic Group: **Present**.

### Step 3: Conclusion
From the analysis, only **Aspirin** contains the carboxylic functional group (COOH). Therefore, it fits the general formula \( C_nH_{2n}O_2 \).

### Final Answer
The correct option is **Aspirin**.

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